Everyone knows that in Python variables are just references and passing such reference to function effectively copies value of the reference to functions local scope, hence any assignment within function has no effect on original variable. Knowing that, this took me by surprise:

>>> def add_eggs(foo):
...     foo += ['eggs']
...
>>> spam = ['spam']
>>> add_eggs(spam)
>>> print spam
['spam', 'eggs']

This seemed to me as an error in Python interpreter, but after checking language reference I discovered it’s not; it’s intended behaviour (emphasis is mine):

An augmented assignment expression like x += 1 can be rewritten as x = x + 1 to achieve a similar, but not exactly equal effect. In the augmented version, x is only evaluated once. Also, when possible, the actual operation is performed in-place, meaning that rather than creating a new object and assigning that to the target, the old object is modified instead.

Quoted after: python docs